Friday, November 30, 2007

7th Grade Nov. 26th

Banana Farmer's Dilemma

A banana farmer has six monkeys who hate each other. They must be kept in pens to separate them from the bananas as well as from each other.
The farmer has created six pens of equal size using 13 equal lengths of fencing. The pens are organized in a row.




Early one morning the farmer discovers someone has stolen one of the lengths of fencing.



How can the farmer reorganize the fencing to make six new pens of equal size with the 12 remaining lengths of fencing?

Have fun. Remember to back up your document in the TO BE GRADED file and submit your responses to:

mathclasshonors@yahoo.com

Ms. Leckman

1 comment:

Anonymous said...

E.W.H.


There are 10990 legs on the bus. I reached this answer through these steps.
There are 7 children, each has two legs, so that’s 14 legs, next each of the 7 children have 7 backpacks, so that’s 7X7+ 49 backpacks in all on the bus, each of these 49 back packs has 7 big cats in it, that’s 343 big cats, 343X4 for the legs and you get another 1372 legs, now each of the big cats has 7 little cats, that’s 343X7 so there are 2401 little cats on the bus, 2401X4 once again for the legs, and you get 9604 legs, 9604+1372+14=1990
This answer can be obtained in this way.
[(7X2)+(7^2X4)+(7^3X4)]

What's my line?

What's my line?