Monday, November 05, 2007

Trying to find the best way

To all,
I have begun reading your posts for last week. I am trying to determine the best way to post these. I may begin a website just for the postings that tend to be multi-media. Give me a couple days to figure this out, I will keep you posted in class.

ms.l.

1 comment:

Anonymous said...

C.H.C.

P.O.W.

Sue and Ann both get the same stationary package that has 150 pieces of paper and 100 letters. I figured this out for Sue because it explains that Sue put three papers in every envelope. If their were 150 pieces of paper and 100 letters and Sue put 3 pieces of paper in one envelope Sue will have 50 envelopes left. I figured out the part for Ann because the problem explains that Ann put one letter in one envelope. Which tells me their will be 50 pieces of paper left because theirs 100 envelopes so you take 150 from 100 so you can find out theirs 50 pieces of paper left.





Ann

150 papers and 100 envelopes
For every 1 letter theirs 1 envelope

150-100=50 which is 50 papers left

Sue

150 papers and 100 envelopes
For every 3 letter theirs 1 envelope

150/3=50 which is the envelopes left

What's my line?

What's my line?