Friday, November 09, 2007

8th Grade POW Nov. 5th

A Day at the Fairs
The problem this week is an old one, in fact over 500 years old. It goes back to the days in Europe when fairs were common in many cities, and merchants would travel from city to city, selling their various goods and buying other items they desired.

It seems that a humble merchant visited three fairs. At the first fair, early in the morning, he doubled his money selling his products, but spent $30 in food and buying other items.

At midday at the second fair, he tripled his money and spent $54. At the third fair in the afternoon he quadrupled his money but spent $72.

Upon his return home to his wife and ten children, late that day, he counted the money he had in his bag; there was $48.
Now, if the merchant returned home with a profit his wife was happy and she was sad if he returned home with less money than when he started with. So tell me: was his wife happy or sad when he returned? And how much did the man gain or lose, respectively?
Remember: although this type of problem could be solved by guess-&-check or reverse analysis, such an approach will not be accepted here. (You may use them separately to verify your answer; however substitution would be the best way to check your answer.) You must construct an equation for credit. Make sure to label the steps for your solution.


Extra Credit (this is very easy this week don’t over look the opportunity!): If you did your work straightforwardly, your next-to-last step of equation work was of the form (m) x = n. The number “n” is in some way rather interesting; what is it?



Good Luck Ms. L.
Many of you were on the right track. Many of you simply forgot the last step. Here is what it should look like. Our good buddy the merchant's wife was happy because the merchant made $19.
We start with the variable “m”, which is the money the merchant began with. During the first fair of trading, he doubled his money, but spent $30of that amount. This expression is: (2m-30)
During the second fair, the merchant tripled his money, but again spent $54. We keep our first expression and add on because he performed these action on the given money from the first fair, which looks like this: [3(2m-30)-54]
During the third and final fair, the merchant quadrupled his money,and again spent $72. We are just adding on again so the full expression for all three fairs looks like this: {4[3(2m-30)-54]-72}
When he went back home to his wife and ten children, he counted his money and found that he had $48. This amount after all the buying selling occurs is what we have left so it is what our expression “equals”, which looks like this: {4[3(2m-30)-54]-72}=48
Now we can just distribute (one of my favorite things to do,) to find our answer.
{4[3(2m-30)-54]-72}=48 (distribute the 3)
{4[6m-90-54]-72}=48 (distribute the 4)
{24m-360-216-72}=48 (Add like terms)
24m-648=48 (Add 648 to both sides)
24m=696 (divide both sides by 24)
m=29
Now we know that the merchant started out the day with $29 and ended up with $48, this gives him a profit of $19. That makes his wife happy(although, I don't know how long $19 will last on 10 children).


Extra Credit: The next-to-last step is where Ax=B (24m=696) is interesting because B (696) is a palindrome. If you do not know what a palindrome is please look it up, it is not just a Language Arts phenomenon. :-)

22 comments:

Anonymous said...

(2x-30)+(3x-54)+ (4x-72)=48
9x-30+-54+-72=48 Combine like terms
9x+-156=48 Combine like terms
+156 +156 Zero Property
9x=204
(1/9)9x=204(1/9) Identity property
X ≈ 22.66

[2(22.66)-30]+(3[22.66]-54)+[4(22.66)-72]=48 substitute
(45.32-30)+(67.98-54)+(90.64-72)=48 Combine like terms
15.32+13.98+18.64=48 Combine like terms
47.94 ≈ 48

The merchant’s wife was happy because the merchant brought home a profit. He started with about $22.66 and ended with $48.00. He gained $25.34.
E.Mu. (>*-*)>

Anonymous said...

(2x+-30)+(3x-54)+(4x-72)=48
Combine like terms
9x+-156=48
9x+(-156+156 )=48+156 Zero property
9x=204
(1/9)9x=(1/9)204 Multiply reciprocal (identity property)
x=$22.66

[2(22.66)+-30]+[3(22.66)-54]+[4(22.66)-72]=48
(45.32-30)+(67.98-54)+(90.64-72)=48
15.32+13.98+18.64=48
29.3+18.64=48
47.94≈48

X=$22.66
Came home with (y)=$48

$22.66<$48
His wife was happy when he came home.
48-22.66=25.34
He gained a profit of $25.34 during his merchanting at the fairs.

K.A.

Anonymous said...

ewh

If we look as this problem as an equation we would see it as
(2x-30) + (3x-54) + (4x-72) = 48
First things first, we should change all the subtraction symbols to addition
[2x + (-30)]+ [3x + (-54)] + [4x + (-72)] = 48
Ok now we should probably combine the like terms in the equation
9x + -156 = 48
Now we need to get 9x by its self, so we use the zero property.
9x + -156 = 48
+ 156 +156
So we are now left with
9x = 204
Ok now we are almost done we just need to multiply both sides by the reciprocal to get x alone.
1/9 (9x) = 204 1/9
And we end up with
1x = 22 and 2/3
Which could be rounded to 23, so yes the merchants wife would be happy, because he started with 23 dollars and ended with 48 so he made a profit of 25 dollars.

Anonymous said...

2x-30+3y-54+4z-72 = 48
9x-156 = 48
+156 +156
9x-0 = 204
1/9*9/1 = 204*1/9
1x = 22.66
x = 22.66

2(22.66)-30+3(22.66)-54+4(22.66)-72 = 48
45.32-30+67.98-54+90.64-72 = 48
15.32+13.98+18.46 = 48
x = 22.66

His wife was happy. In the beginning the merchant left with 22.66 dollars, or (x). He doubled it at the first fair but spent 30 dollars and had 15.32 dollars. At the second fair he tripled his money but spent 54 dollars and left him with 13.98 dollars. He then at the second fair quadrupled his money and spent 72 dollars so that left him with 18.46 dollars. We added it up and he had 48$.
The first step, we got the equation. Next we used “combining like terms”, and then we used the “zero property”. We “multiplied by the reciprocal” and got our answer. We then plugged it in, or substituted our answer and it was correct.

KG

Anonymous said...

At the first fair: doubled
2x-$30=28
+30 +30
2x=58
x=29

2(29)-30=28

At the second fair: tripled
3x-$54=30
+54 +54
3x=84
x=28

3(28)-54=30

At the third fair: quadrupled
4x-$72=$48
+72 +72
(1/4) 4x=120(1/4)
x=30

4(30)-72=48

now that i figured out one of the "x's" now i can use that value"x" for each

in the beginning, he started with 29 dollars. he ended up with a dollars less than what he started with. at the second fair, he started with 28 dollars more which was 30 dollars. At the third fair, he started with 30 dollars and made a profit of 18 more dollars. At the end his wife was satisfied becuase he came up with 19 more dollars than what he started with

v.b

Anonymous said...

One day, a merchant decided to go to three different fairs. At the first fair, he doubled his sellings, but spent $30. At the second fair, he tripled his sellings, but spent $54. At the third fair, he quadrupled his sellings but spent $72. When he came home there was $48 in his bag. His wife said she would be happy is he came back with more money than he started. Was the wife happy or sad? She was happy.

We learned this by making an equation on the word problem: 48=2x-30+3x-54+4x-72.
First we combined like terms (2x, 3x, 4x).
We then got a new equation of 48=9x-30-54-72.
We combined more like terms (30, 54, 72).
We got another new equation that was 48=9x-156.
To figure out what "x" is, you need to use the zero property and add 156 to each side of the equation.
We got an equation now of 204=9x.
We next multiplied each side by the reciprocal of 9 which is 1/9.
After this step we figured out that "x" was $22.66
To check our answer, we used substitution to plug in 22.66 into our equation. We got 48=[2(22.66)-30]+[3(22.66)-54]+[4(22.66)-72]. We simplified and figured out the first bracket; the answer was 15.32.
We then simplified again and figured out the second bracket which was 13.98.
Finally, we simplified and figured out the third bracket; 18.64
Our new equation was 15.32+13.98+18.64.
We simplified and added all of the nubers together and got 47.94. The only reason it was not 48 was because of the repeating decimal in the answer to "x".
We know that she is happy because he started out with $22.66 and ended up with $48.
He gained a total of $25.34.
That is a good gain figuring that he went to three fairs!

48=2x-30+3x-54+4x-72 wrote our equation
48=9x-30-54-72 combined like terms
48=9x-136 combined more like terms
204=9x used the zero property by adding 136 to each side
22.66=x multiplied by the reciprocal which was 1/9
48=2(22.66)-30+3(22.66)-54+4(22.66)-72 substitution
48=45.32-30+67.98-54+90.64-72 simplify (multiplication)
48=15.32+67.98-54+90.64-72 simplify (subtraction)
48=15.32+13.98+90.64-72 simplify (subtraction)
48=15.32+13.64+18.64 simplify (subtraction
48=28.98+18.64 simplify (addition)
48=47.94 simplify (addition)

Anonymous said...

wellllll i first started out my makeing a equation for the amount of money he had after the fair. i made the equation (2x-30)+(3x-54)+(4x-72)=48

i then used the leckman(changeing the sighns)
(2x+-30)+(3x+-54)+(4x+-72)=48

i then combined the like terms of 2x+3x+4x and -30+-54+-72 and i got
9x+-156=48

then i used the zero property and added 156 too both sides of the equation and got
9x+-156=48
+156 +156

next, i multiplyed each side of the equation by the reciperacle of 9x
(1/9)9x=204(1/9)

i then got the answer n i then checked it
X~22.66

i substituted in 22.66 for x
(2*22.66-30)+(3*22.66-54)+(4*22.66-72)=48

i followd the order of operations and mutiplyed 2*22.66, 3*22.66, and 4*22.66
(45.2-30)+(67.98-54)+(90.64-72)=48

i then did the parenthacies
15.2+13.98+18.64=48

i added 15.2 and 13.98 toegther
29.18+18.64=48

finally, i added 29.18 and 18.64
48=48

Anonymous said...

At the first fair: doubled
2x-$30=28
+30 +30
2x=58
x=29

2(29)-30=28

At the second fair: tripled
3x-$54=30
+54 +54
3x=84
x=28

3(28)-54=30

At the third fair: quadrupled
4x-$72=$48
+72 +72
(1/4) 4x=120(1/4)
x=30

4(30)-72=48

2x-30-3y-54-4n-72=48
X=29
Y=28
N=30

now that i figured out one of the "x's" now i can use that value"x" for each

in the beginning, he started with 29 dollars. he ended up with a dollars less than what he started with. at the second fair, he started with 28 dollars more which was 30 dollars. At the third fair, he started with 30 dollars and made a profit of 18 more dollars. At the end his wife was satisfied becuase he came up with 19 more dollars than what he started with

v.b

Anonymous said...

At the first fair:doubled
2x-30=28
+30 +30
(1/2)2x=58(1/2)
x=29

2(29)-30=$28

At the second fair:tripled
3y-54=30
+54 +54
(1/3)3y=84(1/3)
y=28

3(28)-54=$30

At the third fair:quadrupled

4n-72=$48
+72 +72
(1/4)4n=120(1/4)
n=30

4(30)-72=$48

2x-30-3y-54-4n-72=$48

x=29
y=28
n=30

At the end of the day, he went home with $48

In the beginning he started with 29 dollars. He ended up with a dollar less than what he started with which was 28 dollars. At the second fair he started with 28 dollars and he made a profit of 2 dollars more which was 30 dollars. At the third fair he started with 30 dollars and made a profit of 18 more dollars which was $48. At the the end of the day his wife was satisfied because he made a profit of 19 more dollars than what he started with in the beginning.

LN

Anonymous said...

At the 1st fair:doubled
2x-30=28
+30 +30
(1/2)2x=58(1/2)
x=29
2(29)-30=$28

At the 2nd fair:tripled
3y-54=30
+54 +54
(1/3)3y=84(1/3)
y=28
3(28)-54=$30

At the 3rd fair:quadrupled
4n-72=$48
+72 +72
(1/4)4n=102(1/4)
n=30
4(30)-72=$48


2x-30-3y-54-4n-72=$48

x=29
y=28
n=30

At the end of the day, he ended up with $48.

In the beginning he started with 29 dollars. He ended up with a dollar less than what he started with which was 28 dollars. At the second fair he started with 28 dollars and he made a profit of 2 dollars more which was 30 dollars. At the third fair he started with 30 dollars and made a profit of 18 more dollars which was 48 dollar. At the end of the day his wife was satisfied because he made 19 more dollars than what he started with in the beginning.

JV

Anonymous said...

(2x-30)+(3x-54)+(4x-72)=48 zero property
+72 +72
(2x-30)+(3x-54)+4x=120 zero property
+54 +54
(2x-30)+3x+4x=174 zero property
+30 +30
2x+3x+4x=204 combine like terms
(1/9)9x=(1/9)204 identity property
x=22.66

48-22.66=25.34

He made a profit of $25.34 so his wife was happy.

[2(22.66)+-30]+[3(22.66)-54]+[4(22.66)-72]=48
(45.32-30)+(67.98-54)+(90.64-72)=48
15.32+13.98+18.64=48
29.3+18.64=48
47.94≈48

k.a.

Anonymous said...

Our P.O.W. for this week was about a merchant going to three different fairs. At the first fair the merchant doubled his money by selling his products, but spent $30 of it. At the next fair the merchant tripled his money, but spent $54. At the third fair he quadrupled his money, but spent $74. When he got home he counted his money in his bag and ended up with $48. If he returned home with a profit his wife would be happy and if he cam home without a profit his wife would be disappointed. Then the problem asks you if the wife was sad or happy with his return. To solve the situation there would have to be an equation to figure out the total number that the merchant started with. The equation for the situation would be 48=2x-30+3x-54+x-72 with the 48 being his total number of earnings at the end, 2x being his doubled money at the first fair and subtracting the $30 that he spent, 3x being his tripled money and subtracting $54 he spent, and 4x being his quadrupled money and subtracting $72 because that is what he spent.
We wanted to isolate the value of x. To achieve this the first step was to change the signs in the equation to make solving the equation easier(the Leckman) so the rewritten equation would be 48=2x+-30+3x+-52+4x+-72.
Next I combined the like terms which translated the problem into 48=9x-156. Our next step was the zero property so we subtracted 156 from each side of the equation. The equation was now 204=9x and we then multiplied by the reciprocal of 9 so we multiplied each side of the equation by 1/9 which stated that x was equal to $22.66. To see what his profit was you had to subtract $22.66 from $48 and you get $22. 34. When he came home he mad his wife very happy!! To find if my answer was correct I used substitution.


48= 2x – 30 + 3x – 54 +4x – 72
48= 2x + -30 + 3x + - 54 + 4x + -72 the Leckman
48 = 9x + - 156 combining “like terms”
+156 +156 zero property
(1/9)204 = 9x(1/9) multiply by reciprocal
22. 66 = x

SUBSTITUTION
48 = 2(22.66) + -30 + 3(22.66) + -54 + 4(22.66) + -72
48 = 15. 32 + 13. 98 + 18.64
48=48



M.G.

Anonymous said...

= 48
X + -72 = 48
X + -72 * 4 - 54 = 48
X + -72 * 4 – 54 * 3 -30 * 2 = 48






d.c.

Anonymous said...

A merchant went to three fairs. He doubled his selling’s, but spent $30. Then he went to the second fair. He tripled his selling’s and then spent $54. Finally, he went to the third fair. He quadrupled his money, but spent $72.When he came home, there was $48 in his bag. The wife said that she would be happy if he made a profit and sad if he came home with less money then he started with. We needed to know whether or not the wife was happy or sad, and how much money did the merchant gain, or lose.
He figured out that the wife would be very happy. The reason is because he came home with a profit of $25.34.
We figured this out by first writing our equation. Our equation was 48=2x-30+3x-54+4x-72. We then changed the equation to an addition problem. The equation then turned out to be 48=2x-30+3x-54+4x-72.
Next, you added the like terms in the equation. We added 2x, 3x, and 4x. Our equation then turned into 48=9x+-30+-54+-72. Next, we added the like terms of -30, -54, and -72. Our equation then turned into 48=9x+-156.
We next did the zero property. This would isolate 9x so we could find what ''x'' represented. When we added +156 to each side, the new equation equaled 204=9x.
Finally, we multiplied each side by the reciprocal of 9, which was 1/9. When we found out answer, you simplified it and got 22 2/3.
We had to simplify that fraction into money, so the new answer became $22.66.
That answer told us that the merchant started off with $22.66. He then came home with a profit of $25.34 gained.
After we found our answer, we substituted our answer into the equation. The equation came out to be 48=2(22.66)-30+3(22.66)-54+4(22.66)-72. We first started to multiply 2, 3, and 4 by 22.66. After, our equation got 48=45.32-30+67.98-54+90.64-72. We then, just started going across the equation. Final our equation came out to be 48=15.32+13.98+18.64. We added all those numbers together our final answer was $47.94.
So we figured that the wife was happy, because he came home with a profit.
To find how much of a profit he made, we subtracted $22.66 from $48 and got $25.34.

Steps
48= 2x-30+3x-54+4x-72 wrote equation
48= 2x+-30+3x+-54+4x+-72 changed signs into addition problems
48= 9x+-30+-54+-72 added like terms
48= 9x+-156 added like terms again
+156 +156 zero property
204= 9x+0 simplify
(1/9)204 = (1/9)9x multiply by reciprocal
22 2/3 = x simplify
$22.66 = x

48= 2(22.66)-30+3(22.66)-54+4(22.66)-72 substitute
48= 45.32-30+67.98-54+90.64-72 simplify
48= 15.32+13.98+18.64 simplify
48= 47.98
CT

Anonymous said...

A merchant went to three fairs. At the first fair he doubled his earnings, but spent $30 of this profit. At the second fair his money tripled and he spent $54 and at the third fair he quadrupled his money, but spent $72. When he returned home to his wife and ten children he counted his money and discovered that there was $48.
In evaluating the situation there would have to be an equation to figure out the total number that he started with. The equation for the situation would be 48=2x-30+3x-54+x-72 with the 48 representing his total number of earnings at the end, 2x representing his doubled money at the first fair and subtracting the $30 that he spent, 3x representing his tripled money and subtracting $54 he spent, and 4x representing and subtracting $72 as what he spent.
Our goal now was to isolate the value of x. To do this the first step was to change the signs in the equation to make solving the equation easier so the rewritten equation would be 48=2x+-30+3x+-52+4x+-72.
The next step was to combine the like terms which translated the problem into 48=9x-156. Our next step was the zero property so we subtracted 156 from each side of the equation. The equation was now 204=9x and we then multiplied by the reciprocal of 9 so we multiplied each side of the equation by 1/9 which stated that x was equal to $22.66. This reflected the money that he started with and we subtracted this from $48 to figure out the total money that he gained which was $25.34.
In turn, this meant that when he returned home his wife would be happy because he made a profit.
To check if our answer was correct we plugged in $22.66 into the place of x. The substituted equation was 48=2(22.66)-30+3(22.66)-54+4(22.66)-72. The next step was to use the order of operations and multiply which transformed the equation into 48=15.32+13.98+18.64. We then added this together and this equaled 47.94

Steps
48= 2x-30+3x-54+4x-72 Equation
48=2x+-30+3x+-54+4x+-72 Change the signs
48=9x+-30+-54+-72 Combine like terms
48=9x+-156 Combine like terms
+156 + 156 Zero Property
204=9x+0
204=9x Simplify
(1/9)204=9(1/9) Multiply reciprocal
X=22.66

48=2(22.66)-30+3(22.66)-54+4(22.66)-72 Substitute
48= 45.32-30+67.98-54+90.64-72 Simplify
48=15.32+13.98+18.64 Simplify
48= 47.98



DG

Anonymous said...

(2x-30)+(3x-54)+ (4x-72)=48
+72 +72 Zero property
(2x-30)+(3x-54)+4x= 120
+54 +54 Zero property
(2x-30)+3x+4x= 174
+30 +30 Zero property
2x+3x+4x= 204

2x+3x+4x=204
9x=204 Combine like terms
9x=204
(1/9)9x=204(1/9) reciprocal (identity property)
X=22.66



[2(22.66)-30]+(3[22.66]-54)+[4(22.66)-72]=48 substitute
(45.32-30)+(67.98-54)+(90.64-72)=48 Combine like terms
15.32+13.98+18.64=48 Combine like terms
47.94 ≈ 48

The merchant’s wife was happy because the merchant brought home a profit. He started with about $22.66 and ended with $48.00. He gained $25.34.

E.Mu. new version

Anonymous said...

I combined the like terms of the equation and got to an easier equation to work with:
2x-30+3x-54+4x-72=48
9x-156=48
after that I used the zero property by adding 156 to each side and got closer to my answer:
2x-30+3x-54+4x-72=48
9x-156=48
+156 +156
9x-0=204
after that i multiplied both sides by the reciprocal of 9 and got my answer.
2x-30+3x-54+4x-72=48
9x-156=48
+156 +156
9x-0=204
1/9*9x=204*1/9
1x=$22.66
I then plugged in the number and got the answer.
2x-30+3x-54+4x-72=48
9x-156=48
+156 +156
9x-0=204
1/9*9x=204*1/9
1x=$22.66
2(22.66)-30+3(22.66)-54+4(22.66)-72=48
15.32+13.98+18.64=48
X=22.66
His wife was happy because he brought home over double the amount of what he had when he left for the first fair.

Anonymous said...

The first thing that I did was make the scenario into three different equations.:
2x-30=y
3y-54=z
4z-72=48
Then i worked them out by solving them backwards.:
(48+72)/4=z
120/4=30
z=30

(30+54)/3=y
84/3=28
y=28

(28+30)/2=x
58/2=29
x=29
This means that the merchant started with 29 dollars which means he made a pretty good profit, from 29 to 48 dollars.

AR

Anonymous said...

M.G.

The P.O.W. this week gives you the problem of a merchant who goes to three different fairs. The merchant went to the first fair and doubled his money, but spent $30 of it. Then the merchant went to the second fair and tripled his money, but spent $54. At the third fair the merchant quadrupled his money, but spent $72. When the merchant arrived home he counted his money and was left with $48. If the merchant came home with a profit his wife would be happy and if he didn’t come home with a profit his wife would be sad. So, was his wife happy or sad? First, what I did was make the first situation into an equation which was: 2x- 30 which is the merchant’s first fair visit. I figured that the money that he ends with from the first fair visit is the money he begins with for the second fair visit, so I substituted the previous equation: 3(2x-30)- 54. The three is the tripled amount of the merchant’s money for the second fair trip and the fifty- four is want he spent. Next, I simplified the equation by using the distributive property and the simplified that by combing “like terms.” As my result I got 6x-144 so then I substituted “x” because it is the money he will begin with for the third fair trip and I got: 4(6x-144)-72. This is the merchant’s third fair trip where his money has been quadrupled and his 72 dollars spent. I then simplified by using the distributive property: 48=24x-648. My goal was to isolate “x” and so I did this by using the zero property, so I added 648 to 48 and 648 to -648. I got 696=24x. Then I had to multiply 696 and 24 by the reciprocal of 24 which was: 1/24. Finally, I found out what “x” equaled and got 29. This concludes that the merchant started with $29 and came home with a $19 dollar profit so his wife was happy.

EQUATION STEPS:

2x -30
2x + -30 Change signs (the Leckman)
3(2x + -30)-54
6x-90-54 Distributive Property
6x+ -90+ -54 Change signs
6x-144 Combine like terms
6x+-144 Change signs
4(6x+-144)-72
24x-576-72 Distributive Property
24x+-576+-72 Change signs
24x + -648 Combine like terms
48=24x + -648
+648 +648 Zero Property
696=24x+0
696=24x Simplify
(1/24)696= 24x(1/24) Multiply reciprocal
29 = x


SUBSTITUTION STEPS:
2(29)-30 Substitute
2(29)+-30 Change signs
58+ -30 Order of operations
28
6(29)-144
6(29)+-144 Change signs
174+-144 Order of operations
30
24(29)-648
24(29)+-648 Change signs
696+-648 Order of operations
48=48

Anonymous said...

JJ
What I did was I combined like terms from the problem.
2x-30+3x-54+4x-72=48
9x-156=48
I then used the zero property.
9x-156=48
+156 +156
9x-0=204
I multiplied both sides by the reciprocal of 9.
1/9*9-0=204*1/9
I got my final answer.
x=22.66
I then checked the problem.
2(22.66)-30+3(22.66)-54+4(22.66-72=48
After I had checked it I realized that I did it wrong.I was supposed to let the equation go from one thing to the next. I then put it in the way it was supposed to be.
2(22.66)-30+3(22.66)-54+4(22.66-72=48
I got the same thing so after using substitution in the problem two different ways I have came to the conclusion that x=22.66

Anonymous said...

A merchant visited three fairs. At the first fair, early in the morning, he doubled his money selling his products, but spent $30 in food and buying other items. At the second fair, he tripled his money and spent $54. At the third fair he quadrupled his money but spent $72.
Upon his return home to his wife and ten children, late that day, he counted the money he had in his bag; there was $48.
In evaluating the situation there wasn’t a single equation for the given events. Each equation would have to help build into the next one as shown in my steps below:

Steps
1.2x -30
2x + -30 Change signs
3(2x + -30)-54 Substitute X
6x-90-54 Distributive Prop.
6x+ -90+ -54 Change signs
2.6x-144
6x+-144 Change signs
4(6x+-144)-72 Substitute x
3.24x-576-72 Distributive Prop.
24x+-576+-72 Change signs
24x + -648 Combine like terms
48=24x + -648
+648 +648 Zero Property
696=24x+0
696=24x Simplify
(1/24)696= 24x(1/24) Multiply reciprocal
29 = x

The first equation was 2x-30 and this represents the merchant’s first visit to the first fair where his money is doubled, but then spends thirty dollars. We then assume that the money that he ends with from the first visit is the money that he starts with in his second visit to the fair so you would substitute 2x-30 as x, 3(2x-30)-54. In this equation, the three represents the tripled amount in the merchant’s money at the second fair and the fifty-four dollars that he had spent. I then simplified the equation by applying the distributive property and then again simplified this time by combining like terms. The end result was 6x-144 which could now be substituted as x because it’s the amount of money he will start with at the third fair, 4(6x-144)-72. This equation represents the merchant’s third visit to the fair where his money quadrupled and he spent seventy-two dollars. To simplify the equation, I used the distributive property, 24x-576-72. I then combine like terms, 24x-648. Since we know that the merchant arrives home with a total of forty-eight dollars, we can then substitute forty-eight as y, 48=24x-648. I was then able to isolate x by applying the zero property where I added 648 to each side of the equation translating it into 696=24x. I then multiplied each side of the equation by the reciprocal of twenty-four to isolate the value of x. As a result x was equal to 29. This implies that the merchant had started with twenty-nine dollars, but came home with a nineteen dollar profit, which would result in his wife’s happiness.

Substitution Steps:
1. 2(29)-30 Substitute
2(29)+-30 Change signs
58+ -30 Order of operations
28
2. 6(29)-144
6(29)+-144 Change signs
174+-144 Order of operations
30
3. 24(29)-648
24(29)+-648 Change signs
696+-648 Order of operations
48

DG
8th Honors

Anonymous said...

Ms. Leckman, this is JK in 8-9 per.
The man's wife was happy because the man started off with 29 dollars and came home with 48 dollars. This is using reverse analysis so I don't expect credit, I just wanted to do it because I was bored. Okay. See you tomorrow November 15, 2007

What's my line?

What's my line?