Wet and Wild

Well, our first computer lab was delayed due to the sever weather. It has been a while since we have seen down drafts so prevalent and so strong, in our area. To those of you who were present on Friday, what a day huh? And for those of you who were not present, I hope there was no damage to your homes or families. Anybody have some good photos of the trees and lines down, let's post them? So, we will try hitting the lab again on Friday. Until then, enjoy your three (for some four day) holiday and I will see you on Tuesday.

Ms. L.

All Wet

I have not checked and posted all the responses to this POW. However, I am seeing some common themes here some of which elate me and some of which are well...

I am elated to see you all saw the need for the Pythagorean Theorem in this problem!

I also noticed many, if not all of you, used guess and check to find the side lengths of your rectangle and this would be fully acceptable - however you never clearly indicated how you knew you had the correct side lengths. There was no proof that they in fact were correct. It was if you magically pulled them out of the air and viol la, they were correct! If you did not, could not explain how you derived your side lengths I docked you points.

I also noticed that the extra credit was not appropriately taken advantage of, and other tasks were undertaken instead. Please do not overlook this opportunity for extra credit in the future.

Ms. L.


All Wet :

A rectangular lawn has an area of 667 square meters.
Surrounding the lawn is a flower border 4 meters wide.
The border alone has an area of 548 square meters.

A circular sprinkler is installed in the middle of the lawn.

What is the spraying radius of the sprinkler if it covers the entire yard, including the flower border?

Explain, in detail, all the reasoning, algebra, and problem-solving techniques you use to solve this problem. Represent all variables and include key steps and formulas you used. Don't forget to include a check for your answer. Answers may be given to the nearest hundredth. Bonus: What percentage of water is wasted (i.e. water that lands outside the lawn and garden)?

Good luck! :-)

Here is SM post:

667+548=1215
1215 is the total area of the garden.
36 and 33.75
I got these numbers by dividing 1215 by 36 and getting 33.75
Then you cut the rectangle in half to find the circle radius and use the Pythagoras theorem A squared+B squared=C squared. Also subtract it from 8 because that’s the side length of the garden.

(36-8)(33.75-8)
(28)(25.75)
721 squared is 26.85
26.85 is your answer

Here is BB post:

Here is JS post:

Here is Ms. B.'s (aka frogger) :-)

Here is EK's post:

EMK
667 sq meters is the area of the lawn.
Plus a 548 sq meter border. 4 meters wide.

667+548= 1215 square meters.
Then I thouggght you divided by pi. But you don’t.

The square root of 386.94 (1215/ pi) is ………….. 19.671 which is the raaaaaaaaaaadius

Never mind.

Side Lengths: Length: 22.5 Width: 54. We had help from Tyler and tried different numbers.
54 square root + 22.5= 29.84 would be the radius

JW post:

First I gathered all the data that was usable:

The Area of the lawn is 667 square meters.
The flower border is 4 meters wide.
The area of the border is 548 square meters.

So, the rectangular lawn has an area of 667 square meters.
The total area of the lawn and garden is 1215. Next you need the sides that equal 34.8568. The Number needed to equal 667 which is the lawn area. I used the process of elimination, until I found two that could be put in the equation and equal 667
The side lengths that I found that worked was 22.5 and 54.

The height of the triangle is 17.4284

You have to cut the rectangle in half to make a triangle. Then you have to use the formula a squared plus b squared equals c squared. That makes a diameter of 58.4. Then you have to cut that number in half to get the radius. The radius is 29.2, which is the sprinkler radius.

The Radius is 29.25

Here is SV post:

Flowerbed area + area of lawn=y

548+667=1215

Side lengths:
Length: 22.5
Width: 54
First, I found the side lengths of the rectangle with the trial and error process. Then I used the Pythagorean Theorem to figure out the radius.

(A squared + B squared= C squared)

54 square root +22.5= 29.25

Answer: 29.25

And last but not least RB's post:

Happy First Friday

Well, here we are Friday Lab. It will be a bit tricky making sure everyone is in the right place but I think we can do it!

There are some ground rules for those of you that are new to Friday Math Lab.

1. You are here to do math.
2. You come into the lab, log in, and proceed to the Problem of the Week (POW) for your class.
3. POW's are a requirement of the class. It is an assignment and it is graded.
4. You may work with a partner, however the final post needs to be in your own words. (Everyone needs a post so I can give you a grade.)
5. You may use any resources you need on the web, in the book, or with each other to post your solution.
6. All post automatically go to me prior to the web. I will approve it for the web. I will let you know when I have accepted and posted your work. However, keep in mind that I can call you up and tell you it is not finished and you will need to go back and edit your work.
7. Keep in mind from where I sit, I see all of your screens. :-)
8. You must start your post with the intial of your first name and your last name. NEVER USE A WHOLE NAME, NEVER REFER TO ANYONE IN THE CLASS USING A FULL NAME. You may use my whole name.

TIPS:
1. Work in Word first and then cut and paste to the comment box. If you leave the comment box open too long you will lose all of your work. (Also, you can not copy from the comment box and paste in Word. See why this is important in the next bullet.)
2. Always save your work in the Leckman to be graded file. If for some reason your post is lost while you are submitting it, we still have a copy.
3. Use appropriate language, we are live for everyone to see. You are the image of Madison Number One through your voice on the web.

Now on to your task for today:

7th Grade Honors - please read through: Tips for the New 7th Grade AEP, from last years 7th grade. Post your thoughts on their tips and then proceed to the 7th grade page and begin your POW.

8th Grade - Proceed to the 8th Grade page and begin your POW.

Welcome back 8th Honors - Here ya go... You get a choice today. I have a page set up for you if you would like a seperate page or you can keep posting on this page. I am rather proud of your work here and would love to see you stay here, but it is totally your choice. We need to decide which way we want to go. We will proceed from there. :-)

Good luck to all.
Ms. L.